Fix: recursion bug for JS and TS (#1028)
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@ -20,12 +20,12 @@ function forLoopRecur(n) {
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const stack = [];
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const stack = [];
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let res = 0;
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let res = 0;
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// 递:递归调用
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// 递:递归调用
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for (let i = 1; i <= n; i++) {
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for (let i = n; i > 0; i--) {
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// 通过“入栈操作”模拟“递”
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// 通过“入栈操作”模拟“递”
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stack.push(i);
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stack.push(i);
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}
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}
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// 归:返回结果
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// 归:返回结果
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while (stack.length) {
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while (stack.length) {
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// 通过“出栈操作”模拟“归”
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// 通过“出栈操作”模拟“归”
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res += stack.pop();
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res += stack.pop();
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}
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}
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@ -20,12 +20,12 @@ function forLoopRecur(n: number): number {
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const stack: number[] = [];
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const stack: number[] = [];
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let res: number = 0;
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let res: number = 0;
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// 递:递归调用
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// 递:递归调用
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for (let i = 1; i <= n; i++) {
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for (let i = n; i > 0; i--) {
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// 通过“入栈操作”模拟“递”
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// 通过“入栈操作”模拟“递”
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stack.push(i);
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stack.push(i);
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}
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}
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// 归:返回结果
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// 归:返回结果
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while (stack.length) {
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while (stack.length) {
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// 通过“出栈操作”模拟“归”
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// 通过“出栈操作”模拟“归”
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res += stack.pop();
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res += stack.pop();
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}
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}
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@ -67,4 +67,4 @@ console.log(`尾递归函数的求和结果 res = ${res}`);
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res = fib(n);
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res = fib(n);
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console.log(`斐波那契数列的第 ${n} 项为 ${res}`);
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console.log(`斐波那契数列的第 ${n} 项为 ${res}`);
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export {};
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export { };
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