2014-10-20 11:23:39 +08:00
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// Source : https://oj.leetcode.com/problems/longest-substring-without-repeating-characters/
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// Author : Hao Chen
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// Date : 2014-07-19
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2014-10-21 10:49:57 +08:00
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/**********************************************************************************
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*
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2014-10-21 11:39:53 +08:00
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* Given a string, find the length of the longest substring without repeating characters.
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* For example, the longest substring without repeating letters for "abcabcbb" is "abc",
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* which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1.
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2014-10-21 10:49:57 +08:00
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*
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**********************************************************************************/
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2014-10-20 11:23:39 +08:00
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#include <string.h>
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#include <iostream>
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#include <string>
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#include <map>
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using namespace std;
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int lengthOfLongestSubstring1(string s) {
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map<char, int> m;
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int maxLen = 0;
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int lastRepeatPos = -1;
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for(int i=0; i<s.size(); i++){
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if (m.find(s[i])!=m.end() && lastRepeatPos < m[s[i]]) {
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lastRepeatPos = m[s[i]];
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}
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if ( i - lastRepeatPos > maxLen ){
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maxLen = i - lastRepeatPos;
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}
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m[s[i]] = i;
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}
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return maxLen;
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}
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//don't use <map>
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int lengthOfLongestSubstring(string s) {
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const int MAX_CHARS = 256;
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int m[MAX_CHARS];
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memset(m, -1, sizeof(m));
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int maxLen = 0;
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int lastRepeatPos = -1;
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for(int i=0; i<s.size(); i++){
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if (m[s[i]]!=-1 && lastRepeatPos < m[s[i]]) {
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lastRepeatPos = m[s[i]];
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}
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if ( i - lastRepeatPos > maxLen ){
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maxLen = i - lastRepeatPos;
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}
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m[s[i]] = i;
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}
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return maxLen;
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}
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int main(int argc, char** argv)
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{
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string s = "abcabcbb";
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cout << s << " : " << lengthOfLongestSubstring(s) << endl;
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s = "bbbbb";
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cout << s << " : " << lengthOfLongestSubstring(s) << endl;
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s = "bbabcdb";
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cout << s << " : " << lengthOfLongestSubstring(s) << endl;
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if (argc>1){
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s = argv[1];
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cout << s << " : " << lengthOfLongestSubstring(s) << endl;
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}
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return 0;
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}
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