added FindTheDuplicateNumber

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Vally 2015-10-19 23:56:36 +03:00
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// Source : https://leetcode.com/problems/find-the-duplicate-number/
// Author : Calinescu Valentin
// Date : 2015-10-19
/***************************************************************************************
*
* Given an array nums containing n + 1 integers where each integer is between 1 and
* n (inclusive), prove that at least one duplicate number must exist.
* Assume that there is only one duplicate number, find the duplicate one.
*
* Note:
* You must not modify the array (assume the array is read only).
* You must use only constant, O(1) extra space.
* Your runtime complexity should be less than O(n2).
* There is only one duplicate number in the array, but it could be repeated more than
* once.
* Credits:
* Special thanks to @jianchao.li.fighter for adding this problem and creating all test
* cases.
*
***************************************************************************************/
/*
* Solutions
* =========
*
* A simple solution would be to sort the array and then look for equal consecutive elements.
*
* Time Complexity: O(N log N)
* Space Complexity: O(1)
*
*/
#include <algorithm>
class Solution {
public:
int findDuplicate(vector<int>& nums) {
sort(nums.begin(), nums.end());
for(vector<int>::iterator it = nums.begin(); it != nums.end(); ++it)
if(*it == *(it + 1))
return *it;
}
};