added FindTheDuplicateNumber
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// Source : https://leetcode.com/problems/find-the-duplicate-number/
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// Author : Calinescu Valentin
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// Date : 2015-10-19
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/***************************************************************************************
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*
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* Given an array nums containing n + 1 integers where each integer is between 1 and
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* n (inclusive), prove that at least one duplicate number must exist.
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* Assume that there is only one duplicate number, find the duplicate one.
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*
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* Note:
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* You must not modify the array (assume the array is read only).
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* You must use only constant, O(1) extra space.
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* Your runtime complexity should be less than O(n2).
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* There is only one duplicate number in the array, but it could be repeated more than
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* once.
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* Credits:
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* Special thanks to @jianchao.li.fighter for adding this problem and creating all test
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* cases.
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*
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***************************************************************************************/
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/*
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* Solutions
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* =========
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*
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* A simple solution would be to sort the array and then look for equal consecutive elements.
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*
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* Time Complexity: O(N log N)
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* Space Complexity: O(1)
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*
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*/
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#include <algorithm>
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class Solution {
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public:
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int findDuplicate(vector<int>& nums) {
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sort(nums.begin(), nums.end());
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for(vector<int>::iterator it = nums.begin(); it != nums.end(); ++it)
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if(*it == *(it + 1))
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return *it;
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}
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};
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