New Problem Solution - "1845. Seat Reservation Manager"

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Hao Chen 2021-05-03 12:14:32 +08:00
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| # | Title | Solution | Difficulty |
|---| ----- | -------- | ---------- |
|1845|[Seat Reservation Manager](https://leetcode.com/problems/seat-reservation-manager/) | [C++](./algorithms/cpp/seatReservationManager/SeatReservationManager.cpp)|Medium|
|1844|[Replace All Digits with Characters](https://leetcode.com/problems/replace-all-digits-with-characters/) | [C++](./algorithms/cpp/replaceAllDigitsWithCharacters/ReplaceAllDigitsWithCharacters.cpp)|Easy|
|1840|[Maximum Building Height](https://leetcode.com/problems/maximum-building-height/) | [C++](./algorithms/cpp/maximumBuildingHeight/MaximumBuildingHeight.cpp)|Hard|
|1839|[Longest Substring Of All Vowels in Order](https://leetcode.com/problems/longest-substring-of-all-vowels-in-order/) | [C++](./algorithms/cpp/longestSubstringOfAllVowelsInOrder/LongestSubstringOfAllVowelsInOrder.cpp)|Medium|

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// Source : https://leetcode.com/problems/seat-reservation-manager/
// Author : Hao Chen
// Date : 2021-05-03
/*****************************************************************************************************
*
* Design a system that manages the reservation state of n seats that are numbered from 1 to n.
*
* Implement the SeatManager class:
*
* SeatManager(int n) Initializes a SeatManager object that will manage n seats numbered from
* 1 to n. All seats are initially available.
* int reserve() Fetches the smallest-numbered unreserved seat, reserves it, and returns its
* number.
* void unreserve(int seatNumber) Unreserves the seat with the given seatNumber.
*
* Example 1:
*
* Input
* ["SeatManager", "reserve", "reserve", "unreserve", "reserve", "reserve", "reserve", "reserve",
* "unreserve"]
* [[5], [], [], [2], [], [], [], [], [5]]
* Output
* [null, 1, 2, null, 2, 3, 4, 5, null]
*
* Explanation
* SeatManager seatManager = new SeatManager(5); // Initializes a SeatManager with 5 seats.
* seatManager.reserve(); // All seats are available, so return the lowest numbered seat, which is
* 1.
* seatManager.reserve(); // The available seats are [2,3,4,5], so return the lowest of them, which
* is 2.
* seatManager.unreserve(2); // Unreserve seat 2, so now the available seats are [2,3,4,5].
* seatManager.reserve(); // The available seats are [2,3,4,5], so return the lowest of them, which
* is 2.
* seatManager.reserve(); // The available seats are [3,4,5], so return the lowest of them, which
* is 3.
* seatManager.reserve(); // The available seats are [4,5], so return the lowest of them, which is
* 4.
* seatManager.reserve(); // The only available seat is seat 5, so return 5.
* seatManager.unreserve(5); // Unreserve seat 5, so now the available seats are [5].
*
* Constraints:
*
* 1 <= n <= 10^5
* 1 <= seatNumber <= n
* For each call to reserve, it is guaranteed that there will be at least one unreserved seat.
* For each call to unreserve, it is guaranteed that seatNumber will be reserved.
* At most 10^5 calls in total will be made to reserve and unreserve.
******************************************************************************************************/
class SeatManager {
private:
set<int> idle;
public:
SeatManager(int n) {
for(int i=1; i<=n; i++) {
idle.insert(i);
}
}
int reserve() {
auto it = idle.begin();
auto seat = *it;
idle.erase(it);
return seat;
}
void unreserve(int seatNumber) {
idle.insert(seatNumber);
}
};
/**
* Your SeatManager object will be instantiated and called as such:
* SeatManager* obj = new SeatManager(n);
* int param_1 = obj->reserve();
* obj->unreserve(seatNumber);
*/