New Solution "Unique Morse Code Words"
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|859|[Buddy Strings](https://leetcode.com/problems/buddy-strings/description/) | [C++](./algorithms/cpp/buddyStrings/BuddyStrings.cpp)|Easy|
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|858|[Mirror Reflection](https://leetcode.com/problems/mirror-reflection/description/) | [C++](./algorithms/cpp/mirrorReflection/MirrorReflection.cpp)|Medium|
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|837|[Most Common Word](https://leetcode.com/problems/most-common-word/) | [C++](./algorithms/cpp/mostCommonWord/MostCommonWord.cpp)|Easy|
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|804|[Unique Morse Code Words](https://leetcode.com/problems/unique-morse-code-words/description/) | [C++](./algorithms/cpp/uniqueMorseCodeWords/UniqueMorseCodeWords.cpp)|Easy|
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|771|[Jewels and Stones](https://leetcode.com/problems/jewels-and-stones/description) | [C++](./algorithms/cpp/jewelsAndStones/JewelsAndStones.cpp)|Easy|
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|643|[Maximum Average Subarray I](https://leetcode.com/problems/maximum-average-subarray-i/description/) | [C++](./algorithms/cpp/maximumAverageSubarray/MaximumAverageSubarray.I.cpp)|Easy|
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|477|[Total Hamming Distance](https://leetcode.com/problems/total-hamming-distance/) | [C++](./algorithms/cpp/totalHammingDistance/totalHammingDistance.cpp)|Medium|
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algorithms/cpp/uniqueMorseCodeWords/UniqueMorseCodeWords.cpp
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algorithms/cpp/uniqueMorseCodeWords/UniqueMorseCodeWords.cpp
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// Source : https://leetcode.com/problems/unique-morse-code-words/description/
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// Author : Hao Chen
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// Date : 2018-06-29
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/***************************************************************************************
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*
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* International orse Code defines a standard encoding where each letter is mapped to
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* a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c"
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* maps to "-.-.", and so on.
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*
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* For convenience, the full table for the 26 letters of the English alphabet is given
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* below:
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*
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*
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* [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.",
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* "---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
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*
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* Now, given a list of words, each word can be written as a concatenation of the orse
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* code of each letter. For example, "cab" can be written as "-.-.-....-", (which is
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* the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the
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* transformation of a word.
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*
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* Return the number of different transformations among all words we have.
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*
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*
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* Example:
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* Input: words = ["gin", "zen", "gig", "msg"]
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* Output: 2
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* Explanation:
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* The transformation of each word is:
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* "gin" -> "--...-."
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* "zen" -> "--...-."
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* "gig" -> "--...--."
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* "msg" -> "--...--."
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*
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* There are 2 different transformations, "--...-." and "--...--.".
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*
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*
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*
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*
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* Note:
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*
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*
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* The length of words will be at most 100.
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* Each words[i] will have length in range [1, 12].
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* words[i] will only consist of lowercase letters.
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***************************************************************************************/
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class Solution {
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public:
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int uniqueMorseRepresentations(vector<string>& words) {
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string MorseTable[26] = {".-","-...","-.-.","-..",".","..-.","--.",
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"....","..",".---","-.-",".-..","--","-.",
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"---",".--.","--.-",".-.","...","-","..-",
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"...-",".--","-..-","-.--","--.."};
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unordered_map<string, bool> transformations;
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for (auto word : words) {
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string morse;
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for (auto ch : word) {
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morse += MorseTable[ ch - 'a' ];
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}
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transformations[morse]=true;
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}
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return transformations.size();
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}
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};
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