New Solution "Unique Morse Code Words"

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Hao Chen 2018-06-29 09:47:00 +08:00
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|859|[Buddy Strings](https://leetcode.com/problems/buddy-strings/description/) | [C++](./algorithms/cpp/buddyStrings/BuddyStrings.cpp)|Easy|
|858|[Mirror Reflection](https://leetcode.com/problems/mirror-reflection/description/) | [C++](./algorithms/cpp/mirrorReflection/MirrorReflection.cpp)|Medium|
|837|[Most Common Word](https://leetcode.com/problems/most-common-word/) | [C++](./algorithms/cpp/mostCommonWord/MostCommonWord.cpp)|Easy|
|804|[Unique Morse Code Words](https://leetcode.com/problems/unique-morse-code-words/description/) | [C++](./algorithms/cpp/uniqueMorseCodeWords/UniqueMorseCodeWords.cpp)|Easy|
|771|[Jewels and Stones](https://leetcode.com/problems/jewels-and-stones/description) | [C++](./algorithms/cpp/jewelsAndStones/JewelsAndStones.cpp)|Easy|
|643|[Maximum Average Subarray I](https://leetcode.com/problems/maximum-average-subarray-i/description/) | [C++](./algorithms/cpp/maximumAverageSubarray/MaximumAverageSubarray.I.cpp)|Easy|
|477|[Total Hamming Distance](https://leetcode.com/problems/total-hamming-distance/) | [C++](./algorithms/cpp/totalHammingDistance/totalHammingDistance.cpp)|Medium|

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// Source : https://leetcode.com/problems/unique-morse-code-words/description/
// Author : Hao Chen
// Date : 2018-06-29
/***************************************************************************************
*
* International orse Code defines a standard encoding where each letter is mapped to
* a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c"
* maps to "-.-.", and so on.
*
* For convenience, the full table for the 26 letters of the English alphabet is given
* below:
*
*
* [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.",
* "---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
*
* Now, given a list of words, each word can be written as a concatenation of the orse
* code of each letter. For example, "cab" can be written as "-.-.-....-", (which is
* the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the
* transformation of a word.
*
* Return the number of different transformations among all words we have.
*
*
* Example:
* Input: words = ["gin", "zen", "gig", "msg"]
* Output: 2
* Explanation:
* The transformation of each word is:
* "gin" -> "--...-."
* "zen" -> "--...-."
* "gig" -> "--...--."
* "msg" -> "--...--."
*
* There are 2 different transformations, "--...-." and "--...--.".
*
*
*
*
* Note:
*
*
* The length of words will be at most 100.
* Each words[i] will have length in range [1, 12].
* words[i] will only consist of lowercase letters.
***************************************************************************************/
class Solution {
public:
int uniqueMorseRepresentations(vector<string>& words) {
string MorseTable[26] = {".-","-...","-.-.","-..",".","..-.","--.",
"....","..",".---","-.-",".-..","--","-.",
"---",".--.","--.-",".-.","...","-","..-",
"...-",".--","-..-","-.--","--.."};
unordered_map<string, bool> transformations;
for (auto word : words) {
string morse;
for (auto ch : word) {
morse += MorseTable[ ch - 'a' ];
}
transformations[morse]=true;
}
return transformations.size();
}
};