2015-10-18 10:42:52 +08:00

42 lines
1.2 KiB
C++

// Source : https://oj.leetcode.com/problems/jump-game/
// Author : Hao Chen
// Date : 2014-06-27
/**********************************************************************************
*
* Given an array of non-negative integers, you are initially positioned at the first index of the array.
*
* Each element in the array represents your maximum jump length at that position.
*
* Determine if you are able to reach the last index.
*
* For example:
* A = [2,3,1,1,4], return true.
*
* A = [3,2,1,0,4], return false.
*
*
**********************************************************************************/
class Solution {
public:
bool canJump(int A[], int n) {
if (n<=0) return false;
// the basic idea is traverse array, maintain the most far can go
int coverPos=0;
// the condition i<=coverPos means traverse all of covered position
for(int i=0; i<=coverPos && i<n; i++){
if (coverPos < A[i] + i){
coverPos = A[i] + i;
}
if (coverPos>=n-1){
return true;
}
}
return false;
}
};