2016-11-13 11:59:17 +08:00

52 lines
1.3 KiB
C++

// Source : https://leetcode.com/problems/third-maximum-number/
// Author : Hao Chen
// Date : 2016-11-12
/***************************************************************************************
*
* Given a non-empty array of integers, return the third maximum number in this array.
* If it does not exist, return the maximum number. The time complexity must be in O(n).
*
* Example 1:
*
* Input: [3, 2, 1]
*
* Output: 1
*
* Explanation: The third maximum is 1.
*
* Example 2:
*
* Input: [1, 2]
*
* Output: 2
*
* Explanation: The third maximum does not exist, so the maximum (2) is returned
* instead.
*
* Example 3:
*
* Input: [2, 2, 3, 1]
*
* Output: 1
*
* Explanation: Note that the third maximum here means the third maximum distinct
* number.
* Both numbers with value 2 are both considered as second maximum.
***************************************************************************************/
class Solution {
public:
int nMax(vector<int>& nums, int n) {
set<int> topN;
for(auto num : nums) {
topN.insert(num);
if (topN.size() > n) topN.erase(topN.begin());
}
return (topN.size() >= n) ? *(topN.begin()) : *(topN.rbegin());
}
int thirdMax(vector<int>& nums) {
return nMax(nums, 3);
}
};