60 lines
1.3 KiB
C++
60 lines
1.3 KiB
C++
// Source : https://oj.leetcode.com/problems/length-of-last-word/
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// Author : Hao Chen
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// Date : 2014-07-01
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/**********************************************************************************
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*
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* Given a string s consists of upper/lower-case alphabets and empty space characters ' ',
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* return the length of last word in the string.
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*
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* If the last word does not exist, return 0.
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*
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* Note: A word is defined as a character sequence consists of non-space characters only.
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*
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* For example,
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* Given s = "Hello World",
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* return 5.
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*
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*
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**********************************************************************************/
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#include <stdio.h>
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#include <ctype.h>
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int lengthOfLastWord(const char *s) {
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if ( !s ||!*s ) return 0;
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int wordLen=0;
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int cnt=0;
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for (;*s!='\0';s++) {
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if (isalpha(*s)){
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cnt++;
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}
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if (!isalpha(*s)){
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if (cnt>0){
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wordLen = cnt;
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}
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cnt=0;
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}
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}
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return cnt>0 ? cnt : wordLen;
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}
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int main(int argc, char** argv)
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{
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const char* p;
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p = "hello world";
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printf("%s, %d\n", p, lengthOfLastWord(p));
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p = "a";
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printf("%s, %d\n", p, lengthOfLastWord(p));
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if(argc>1){
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p = argv[1];
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printf("%s, %d\n", p, lengthOfLastWord(p));
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}
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}
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