2015-10-18 10:42:52 +08:00

87 lines
1.9 KiB
C++

// Source : https://oj.leetcode.com/problems/simplify-path/
// Author : Hao Chen
// Date : 2014-10-09
/**********************************************************************************
*
* Given an absolute path for a file (Unix-style), simplify it.
*
* For example,
* path = "/home/", => "/home"
* path = "/a/./b/../../c/", => "/c"
*
*
* Corner Cases:
*
* Did you consider the case where path = "/../"?
* In this case, you should return "/".
* Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
* In this case, you should ignore redundant slashes and return "/home/foo".
*
*
**********************************************************************************/
#include <iostream>
#include <string>
#include <vector>
#include <sstream>
using namespace std;
vector<string> &split(const string &s, char delim, vector<string> &elems) {
stringstream ss(s);
string item;
while (getline(ss, item, delim)) {
elems.push_back(item);
}
return elems;
}
vector<string> split(const string &s, char delim) {
vector<string> elems;
split(s, delim, elems);
return elems;
}
string simplifyPath(string path) {
string result;
vector<string> elems = split(path, '/');
int ignor = 0;
for(int i=elems.size()-1; i>=0; i--) {
if (elems[i]=="" || elems[i]=="." ){
continue;
}
if (elems[i]==".."){
ignor++;
continue;
}
if (ignor>0){
ignor--;
continue;
}
if (result.size()==0){
result = "/" + elems[i];
}else{
result = "/" + elems[i] + result;
}
}
return result.size() ? result : "/";
}
int main(int argc, char** argv)
{
string path("/a/./b/../../c/");
if (argc > 1 ){
path = argv[1];
}
cout << path << " : " << simplifyPath(path) << endl;
}