57 lines
1.8 KiB
C++

// Source : https://leetcode.com/problems/check-if-one-string-swap-can-make-strings-equal/
// Author : Hao Chen
// Date : 2021-03-19
/*****************************************************************************************************
*
* You are given two strings s1 and s2 of equal length. A string swap is an operation where you choose
* two indices in a string (not necessarily different) and swap the characters at these indices.
*
* Return true if it is possible to make both strings equal by performing at most one string swap on
* exactly one of the strings. Otherwise, return false.
*
* Example 1:
*
* Input: s1 = "bank", s2 = "kanb"
* Output: true
* Explanation: For example, swap the first character with the last character of s2 to make "bank".
*
* Example 2:
*
* Input: s1 = "attack", s2 = "defend"
* Output: false
* Explanation: It is impossible to make them equal with one string swap.
*
* Example 3:
*
* Input: s1 = "kelb", s2 = "kelb"
* Output: true
* Explanation: The two strings are already equal, so no string swap operation is required.
*
* Example 4:
*
* Input: s1 = "abcd", s2 = "dcba"
* Output: false
*
* Constraints:
*
* 1 <= s1.length, s2.length <= 100
* s1.length == s2.length
* s1 and s2 consist of only lowercase English letters.
******************************************************************************************************/
class Solution {
public:
bool areAlmostEqual(string s1, string s2) {
int p[2]={0};
int diff=0;
for(int i=0; i<s1.size(); i++){
if (s1[i] ==s2[i]) continue;
if (diff < 2) p[diff] = i;
diff++;
}
return (diff==0) || ( (diff == 2) && s1[p[0]] == s2[p[1]] && s1[p[1]] == s2[p[0]]);
}
};