2015-10-18 10:42:52 +08:00

62 lines
1.5 KiB
C++

// Source : https://oj.leetcode.com/problems/zigzag-conversion/
// Author : Hao Chen
// Date : 2014-07-17
/**********************************************************************************
*
* The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this:
* (you may want to display this pattern in a fixed font for better legibility)
*
* P A H N
* A P L S I I G
* Y I R
*
* And then read line by line: "PAHNAPLSIIGYIR"
*
* Write the code that will take a string and make this conversion given a number of rows:
*
* string convert(string text, int nRows);
*
* convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
*
*
**********************************************************************************/
#include <iostream>
#include <vector>
#include <string>
using namespace std;
string convert(string s, int nRows) {
//The cases no need to do anything
if (nRows<=1 || nRows>=s.size()) return s;
vector<string> r(nRows);
int row = 0;
int step = 1;
for(int i=0; i<s.size(); i ++) {
if (row == nRows-1) step = -1;
if (row == 0) step = 1;
//cout << row <<endl;
r[row] += s[i];
row += step;
}
string result;
for (int i=0; i<nRows; i++){
result += r[i];
}
return result;
}
int main(int argc, char**argv){
string s;
int r;
s = "PAYPALISHIRING";
r = 3;
cout << s << " : " << convert(s, 3) << endl;
}