From baf15fc0e48ec325f93c089c02c2c24148b11105 Mon Sep 17 00:00:00 2001
From: guanjihuan <34735497+guanjihuan@users.noreply.github.com>
Date: Fri, 23 Jul 2021 19:26:47 +0800
Subject: [PATCH] update

---
 ...ind_directory_with_file_number_not_eq_3.py | 26 -------------------
 1 file changed, 26 deletions(-)
 delete mode 100755 language_learning/2021.05.14_zotero/find_directory_with_file_number_not_eq_3.py

diff --git a/language_learning/2021.05.14_zotero/find_directory_with_file_number_not_eq_3.py b/language_learning/2021.05.14_zotero/find_directory_with_file_number_not_eq_3.py
deleted file mode 100755
index 52d68b2..0000000
--- a/language_learning/2021.05.14_zotero/find_directory_with_file_number_not_eq_3.py
+++ /dev/null
@@ -1,26 +0,0 @@
-# 在E:\zotero\storage里的每个文件夹中一般有3个文件（包括隐藏文件），有个别无法解析或其他原因，会只有1个文件或者2个文件。这个其实没什么影响，但如果有强迫症可以通过以下python代码找出文件个数不等于3的文件夹。
-
-import os
-
-def find_files_and_directory(path):
-    file = []
-    directory = []
-    for path in path:
-        filenames = os.listdir(path)
-        for filename in filenames:
-            filename = os.path.join(path,filename) 
-            if os.path.isfile(filename): # 如果是文件
-                file.append(filename) 
-            else:  # 如果是文件夹
-                directory.append(filename)
-    return file, directory
-
-file, directory = find_files_and_directory(['E:/zotero/storage'])
-
-i0 = 0
-for path in directory:
-    file, directory = find_files_and_directory([path])
-    if len(file)!=3:
-        i0 += 1
-        print(path, '文件夹中有', len(file), '个文件')
-print('文件夹中文件个数不等于3的总个数:', i0)
\ No newline at end of file